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Q: What are the square numbers between 3 and 145?

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sqrt(1453) = [sqrt(145)]3 = 145(3)(1/2) = 1746.03121393 approximately

step 1: list all of the prime numbers that go into 36 and 145. 2*2*3*3=36 5*29=145 step 2: find all the common prime numbers between both sets. because there are no common prime numbers, the answer has to be 1.

Write both numbers as decimal numbers, then look for terminating decimals between the two.

The square root of 3 will lie between 1 and 2.

The answer is 2 and 3

all numbers in the range -√130 to √130, or approximately -11.4 to 11.4 lie between the square root of 130. So two numbers that lie between the square root of 130 are 1 and 2. ---------------------------------------- If you meant: What two whole numbers does the square root of 130 lie between? Then √130 lies between 11 and 12.

Maybe 2an 3

3 and 4 since 3^2 is 9 an 4^2 is 16

Yes

Between 3 & 4

14 is between 9 and 16 meaning the number which needs to be multiplied by itself (the square root) is between 3 and 4.

3 and 4

They are 3 and 4

i hace no idea

The square root of 14 lies between 3 and 4.

3 and 4

You can solve this by inspection. Since the square of 3 is less than 13, and the square of 4 is more than 13, it follows that the square root of 13 is between those two numbers.

145

3 and 4

3 squared equals 9. 4 squared equals 16. So the square root of 10 must be between 3 and 4.

It's between 2 and 3. You know this because the next two surrounding perfects squares are 4 and 9, which have square roots of 2 and 3 respectively.

-39

Not "number", but "numbers" - there are infinitely many. For a start, get a decimal approximation (on your calculator) for the square root of 2 and 3, then get some terminating decimals that are between those.

The square root of 6 lies between 2 and 3.

3